Question

Put these numbers in order from least to greatest: -3pi, pi^2, 8

Answer 1

To arrange the numbers \(-3\pi\), \(\pi^2\), and \(8\) from least to greatest, we first need to approximate the numerical values of each:

1. **Calculate \(-3\pi\)**:
\[
\pi \approx 3.14 \quad \Rightarrow \quad -3\pi \approx -3 \times 3.14 \approx -9.42
\]

2. **Calculate \(\pi^2\)**:
\[
\pi^2 \approx (3.14)^2 \approx 9.86
\]

3. **8 is simply 8**.

Now we have:

- \(-3\pi \approx -9.42\)
- \(\pi^2 \approx 9.86\)
- \(8\)

Now we compare these values:
- \(-9.42 < 8 < 9.86\)

Thus, the order from least to greatest is:

\[
-3\pi, 8, \pi^2
\]