Question

Put these numbers in order from least to greatest: √56,-3,4pi

Answer 1

To order the numbers \(\sqrt{56}\), \(-3\), and \(4\pi\) from least to greatest, we first need to evaluate each number.

1. **\(\sqrt{56}\)** can be simplified:
\[
\sqrt{56} = \sqrt{4 \times 14} = \sqrt{4} \times \sqrt{14} = 2\sqrt{14}
\]
To estimate \(\sqrt{14}\):
\[
3.74^2 = 14 \quad (\text{approximately})
\]
Thus:
\[
2\sqrt{14} \approx 2 \times 3.74 \approx 7.48
\]

2. **\(4\pi\)** can be calculated:
\[
4\pi \approx 4 \times 3.14 \approx 12.56
\]

Now, we have approximated values:
- \(\sqrt{56} \approx 7.48\)
- \(-3\)
- \(4\pi \approx 12.56\)

Next, we compare these values:
- \(-3\) is less than \(\sqrt{56}\)
- \(\sqrt{56} \approx 7.48\) is less than \(4\pi \approx 12.56\)

Putting these values in order from least to greatest, we have:
\[
-3, \sqrt{56}, 4\pi
\]

Thus, the final order is:
\[
\boxed{-3, \sqrt{56}, 4\pi}
\]