Identify the vertex of y=−10(x+15)^2−18 .(1 point) Responses (−15,−18) left parenthesis negative 15 comma negative 18 right parenthesis (−10,−15) left parenthesis negative 10 comma negative 15 right parenthesis (−150,−18) left parenthesis negative 150 comma negative 18 right parenthesis (15,−18) left parenthesis 15 comma negative 18 right parenthesis

1 answer

The equation given is in vertex form, which is \( y = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola.

In your equation, \( y = -10(x + 15)^2 - 18 \), we can see that:

  • The term \((x + 15)\) can be rewritten as \((x - (-15))\), which indicates that \( h = -15 \).
  • The constant term at the end, \( -18 \), indicates that \( k = -18 \).

Therefore, the vertex of the parabola is:

\((-15, -18)\).

Thus, the correct answer is \((-15, -18)\).