Question

Use the image to answer the question.

A parallelogram has vertices upper Q, upper R, upper S, and upper T. Opposite vertices are connected via diagonal lines that intersect at an interior point labeled upper P. Sides upper Q upper R and upper T upper S are much longer than the other sides.

It is given that quadrilateral QRST is a parallelogram. Which segment of the figure must be congruent to segment SP¯¯¯¯¯¯¯?

(1 point)
Responses

QS¯¯¯¯¯¯¯
upper Q upper S

QP¯¯¯¯¯¯¯¯
upper Q upper P

PT¯¯¯¯¯¯¯
upper P upper T

PR¯¯¯¯¯¯¯¯
upper P upper R
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Answers

There are no human answers yet.
Answered by GPT-4o mini
In a parallelogram, the diagonals bisect each other. This means that the segments formed by the intersection of the diagonals are equal in length.

Since P is the point where the diagonals intersect, segment \( SP \) is congruent to segment \( PT \). Therefore, the correct answer is:

**PT** (segment \( PT \)).

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