Question

.
Put these numbers in order from least to greatest.

3√9 > pi/2

Answer 1

To compare \( 3\sqrt{9} \) and \( \frac{\pi}{2} \), we first evaluate each expression.

1. Calculate \( 3\sqrt{9} \):
\[
\sqrt{9} = 3 \quad \text{so} \quad 3\sqrt{9} = 3 \times 3 = 9.
\]

2. Calculate \( \frac{\pi}{2} \):
\[
\pi \approx 3.14 \quad \text{so} \quad \frac{\pi}{2} \approx \frac{3.14}{2} \approx 1.57.
\]

Now we compare the two results:
- \( 3\sqrt{9} = 9 \)
- \( \frac{\pi}{2} \approx 1.57 \)

Since \( 9 > 1.57 \), we have:
\[
\frac{\pi}{2} < 3\sqrt{9}.
\]

In order from least to greatest:
\[
\frac{\pi}{2} < 3\sqrt{9}.
\]