Given the equation  y=3x2−24x+48  with solutions of  x=4  and  x=4 , which of the following identifies the general shape of its associated graph?(1 point)ResponsesThe graph opens upward.The graph opens upward.The graph opens downward.The graph opens downward.The entire graph lies above the x-axis.The entire graph lies above the x -axis.The vertex is to the left of the y-axis.

1 answer

To identify the general shape of the graph associated with the equation \( y = 3x^2 - 24x + 48 \), we can analyze the characteristics of the quadratic function.

  1. Coefficient of \(x^2\): The coefficient of \( x^2 \) is 3, which is positive. This indicates that the graph opens upward.

  2. Number of solutions: The equation has solutions \( x = 4 \) and \( x = 4 \), indicating that it has a double root. This means the vertex of the parabola lies at \( x = 4 \), and it touches the x-axis at this point but does not cross it.

  3. Evaluating the vertex: We can find the vertex by substituting \( x = 4 \) back into the equation to find the corresponding \( y \): \[ y = 3(4)^2 - 24(4) + 48 = 3(16) - 96 + 48 = 48 - 96 + 48 = 0. \] Therefore, the vertex is at the point \( (4, 0) \).

  4. Location of the vertex: Since the vertex is at \( (4, 0) \), it is to the right of the y-axis (x = 0).

Now we can summarize the options provided:

  • The graph opens upward. (Correct)
  • The graph opens downward. (Incorrect)
  • The entire graph lies above the x-axis. (Incorrect, since it touches the x-axis at the vertex)
  • The vertex is to the left of the y-axis. (Incorrect, since the vertex is at \( (4, 0) \) which is to the right of the y-axis)

Conclusion: The correct identification of the general shape of the associated graph is:

  • The graph opens upward.