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Which of the following inequalities is `(2,2)` a solution? (Select all that apply.) y<-2x+1 y ≥ 3x-2 y>x-1Question
which of the following inequalities is (2,2) a solution?
SELECT ALL THAT APPLY
a y < -2x + 1
b y > 3x - 2
c y > x - 1
SELECT ALL THAT APPLY
a y < -2x + 1
b y > 3x - 2
c y > x - 1
Answers
Answered by
GPT-4o mini
To determine which inequalities the point (2, 2) satisfies, we will substitute \(x = 2\) and \(y = 2\) into each inequality and check if the inequality holds.
### a) \(y < -2x + 1\)
Substituting \(x = 2\) and \(y = 2\):
\[
2 < -2(2) + 1
\]
Calculating the right side:
\[
-2(2) + 1 = -4 + 1 = -3
\]
So the inequality is:
\[
2 < -3 \quad \text{(False)}
\]
### b) \(y > 3x - 2\)
Substituting \(x = 2\) and \(y = 2\):
\[
2 > 3(2) - 2
\]
Calculating the right side:
\[
3(2) - 2 = 6 - 2 = 4
\]
So the inequality is:
\[
2 > 4 \quad \text{(False)}
\]
### c) \(y > x - 1\)
Substituting \(x = 2\) and \(y = 2\):
\[
2 > 2 - 1
\]
Calculating the right side:
\[
2 - 1 = 1
\]
So the inequality is:
\[
2 > 1 \quad \text{(True)}
\]
### Conclusion
The only inequality that (2, 2) satisfies is:
**c) \(y > x - 1\)**
So the answer is **c only**.
### a) \(y < -2x + 1\)
Substituting \(x = 2\) and \(y = 2\):
\[
2 < -2(2) + 1
\]
Calculating the right side:
\[
-2(2) + 1 = -4 + 1 = -3
\]
So the inequality is:
\[
2 < -3 \quad \text{(False)}
\]
### b) \(y > 3x - 2\)
Substituting \(x = 2\) and \(y = 2\):
\[
2 > 3(2) - 2
\]
Calculating the right side:
\[
3(2) - 2 = 6 - 2 = 4
\]
So the inequality is:
\[
2 > 4 \quad \text{(False)}
\]
### c) \(y > x - 1\)
Substituting \(x = 2\) and \(y = 2\):
\[
2 > 2 - 1
\]
Calculating the right side:
\[
2 - 1 = 1
\]
So the inequality is:
\[
2 > 1 \quad \text{(True)}
\]
### Conclusion
The only inequality that (2, 2) satisfies is:
**c) \(y > x - 1\)**
So the answer is **c only**.
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