To rearrange the formula for the volume of a box, \( V = lwh \), to solve for the width (\( w \)), you would divide both sides by \( lh \).
Starting with:
\[ V = lwh \]
Dividing both sides by \( lh \) gives:
\[ w = \frac{V}{lh} \]
When justifying this rearrangement to solve for \( w \), you can analyze the units:
- The volume \( V \) is in cubic inches (\( in.^3 \)).
- The length \( l \) and height \( h \) are both in linear inches (\( in. \)), so the product \( lh \) is in square inches (\( in.^2 \)).
Thus, the units for \( w \) would be:
\[ \frac{in.^3}{in.^2} = in. \]
This means that the correct representation of the remaining units when justifying your rearrangement to solve for the width is:
**in.^3/in.^2 = in.**