Question
Setting StartFraction 7 over 3 EndFraction equal to which ratio would result in a valid proportion?
StartFraction 9 over 49 EndFraction
StartFraction 18 over 42 EndFraction
StartFraction 42 over 18 EndFraction
StartFraction 49 over 9 EndFraction
StartFraction 9 over 49 EndFraction
StartFraction 18 over 42 EndFraction
StartFraction 42 over 18 EndFraction
StartFraction 49 over 9 EndFraction
Answers
GPT-4o mini
To determine which ratio results in a valid proportion when set equal to \( \frac{7}{3} \), we need to check if the cross products of the fractions are equal. A proportion states that two ratios are equal, so if we set \( \frac{7}{3} = \frac{a}{b} \), then we must have:
\[
7b = 3a
\]
Now, let's evaluate each option:
1. **Option 1: \( \frac{9}{49} \)**
\[
7 \cdot 49 \quad \text{and} \quad 3 \cdot 9
\]
\[
343 \quad \text{and} \quad 27
\]
\( 343 \neq 27 \) (not proportional)
2. **Option 2: \( \frac{18}{42} \)**
\[
7 \cdot 42 \quad \text{and} \quad 3 \cdot 18
\]
\[
294 \quad \text{and} \quad 54
\]
\( 294 \neq 54 \) (not proportional)
3. **Option 3: \( \frac{42}{18} \)**
\[
7 \cdot 18 \quad \text{and} \quad 3 \cdot 42
\]
\[
126 \quad \text{and} \quad 126
\]
\( 126 = 126 \) (proportional)
4. **Option 4: \( \frac{49}{9} \)**
\[
7 \cdot 9 \quad \text{and} \quad 3 \cdot 49
\]
\[
63 \quad \text{and} \quad 147
\]
\( 63 \neq 147 \) (not proportional)
Thus, the ratio that results in a valid proportion with \( \frac{7}{3} \) is:
\[
\frac{42}{18}
\]
\[
7b = 3a
\]
Now, let's evaluate each option:
1. **Option 1: \( \frac{9}{49} \)**
\[
7 \cdot 49 \quad \text{and} \quad 3 \cdot 9
\]
\[
343 \quad \text{and} \quad 27
\]
\( 343 \neq 27 \) (not proportional)
2. **Option 2: \( \frac{18}{42} \)**
\[
7 \cdot 42 \quad \text{and} \quad 3 \cdot 18
\]
\[
294 \quad \text{and} \quad 54
\]
\( 294 \neq 54 \) (not proportional)
3. **Option 3: \( \frac{42}{18} \)**
\[
7 \cdot 18 \quad \text{and} \quad 3 \cdot 42
\]
\[
126 \quad \text{and} \quad 126
\]
\( 126 = 126 \) (proportional)
4. **Option 4: \( \frac{49}{9} \)**
\[
7 \cdot 9 \quad \text{and} \quad 3 \cdot 49
\]
\[
63 \quad \text{and} \quad 147
\]
\( 63 \neq 147 \) (not proportional)
Thus, the ratio that results in a valid proportion with \( \frac{7}{3} \) is:
\[
\frac{42}{18}
\]
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