Question
Add and Subtract Radicals Practice
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Question
Add 28–√+38–√
.
Answers
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Answered by
GPT-4o mini
To add the radicals \( \sqrt{28} \) and \( \sqrt{38} \), first simplify \( \sqrt{28} \).
1. Simplify \( \sqrt{28} \):
- \( \sqrt{28} = \sqrt{4 \times 7} = \sqrt{4} \sqrt{7} = 2\sqrt{7} \)
Now, we have:
\[
2\sqrt{7} + \sqrt{38}
\]
Since \( \sqrt{28} \) is simplified, we can now write:
\[
2\sqrt{7} + \sqrt{38}
\]
This expression cannot be simplified further because \( \sqrt{7} \) and \( \sqrt{38} \) are not like radicals.
Therefore, the final result is:
\[
2\sqrt{7} + \sqrt{38}
\]
1. Simplify \( \sqrt{28} \):
- \( \sqrt{28} = \sqrt{4 \times 7} = \sqrt{4} \sqrt{7} = 2\sqrt{7} \)
Now, we have:
\[
2\sqrt{7} + \sqrt{38}
\]
Since \( \sqrt{28} \) is simplified, we can now write:
\[
2\sqrt{7} + \sqrt{38}
\]
This expression cannot be simplified further because \( \sqrt{7} \) and \( \sqrt{38} \) are not like radicals.
Therefore, the final result is:
\[
2\sqrt{7} + \sqrt{38}
\]
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