Let's start with the original dimensions of the painting, which are 16 inches by 40 inches.
-
First Reduction (Scale Factor of \( \frac{1}{14} \)):
- Smaller dimension: \( 16 \times \frac{1}{14} = \frac{16}{14} = \frac{8}{7} \) inches
- Larger dimension: \( 40 \times \frac{1}{14} = \frac{40}{14} = \frac{20}{7} \) inches
After the first reduction, the dimensions are approximately \( 1.14 \) inches by \( 2.86 \) inches (or exactly \( \frac{8}{7} \) inches by \( \frac{20}{7} \) inches).
-
Second Reduction (Scale Factor of \( \frac{1}{12} \)):
- Smaller dimension: \( \frac{8}{7} \times \frac{1}{12} = \frac{8}{84} = \frac{2}{21} \) inches
- Larger dimension: \( \frac{20}{7} \times \frac{1}{12} = \frac{20}{84} = \frac{5}{21} \) inches
After the second reduction, the dimensions are approximately \( 0.10 \) inches by \( 0.24 \) inches (or exactly \( \frac{2}{21} \) inches by \( \frac{5}{21} \) inches).
Finally, writing the smaller dimension first and the larger dimension second, the dimensions of the postcard are:
\[
\frac{2}{21} \text{ inches by } \frac{5}{21} \text{ inches}
\]
If we convert these to decimal form for easier understanding:
- \( \frac{2}{21} \approx 0.095 \) inches
- \( \frac{5}{21} \approx 0.238 \) inches
Thus, we can say the dimensions of the postcard are approximately 0.095 inches by 0.238 inches.