Question
The diameter, D, of thr sphere is 18.8 m. Calculate the spheres volume, V.
Use the value 3.14 for n, and round your answer to the nearest tenth. (Do not round any intermediate computations.)
Use the value 3.14 for n, and round your answer to the nearest tenth. (Do not round any intermediate computations.)
Answers
GPT-4o mini
To calculate the volume \( V \) of a sphere, we can use the formula:
\[
V = \frac{4}{3} \pi r^3
\]
where \( r \) is the radius of the sphere. The radius is half of the diameter.
Given that the diameter \( D = 18.8 \) m, we can find the radius:
\[
r = \frac{D}{2} = \frac{18.8}{2} = 9.4 \text{ m}
\]
Now, we can substitute the value of \( r \) into the volume formula. Using \( \pi \approx 3.14 \):
\[
V = \frac{4}{3} \times 3.14 \times (9.4)^3
\]
First, calculate \( (9.4)^3 \):
\[
9.4^3 = 9.4 \times 9.4 \times 9.4 = 830.584
\]
Now, substitute \( 9.4^3 \) into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 830.584
\]
Next, calculate \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 \approx 4.18666667 \text{ (approximately 4.19)}
\]
Now, continue calculating the volume:
\[
V \approx 4.18666667 \times 830.584 \approx 3477.797
\]
Finally, round this value to the nearest tenth:
\[
V \approx 3477.8 \, \text{m}^3
\]
Therefore, the volume of the sphere is approximately:
\[
\boxed{3477.8 \, \text{m}^3}
\]
\[
V = \frac{4}{3} \pi r^3
\]
where \( r \) is the radius of the sphere. The radius is half of the diameter.
Given that the diameter \( D = 18.8 \) m, we can find the radius:
\[
r = \frac{D}{2} = \frac{18.8}{2} = 9.4 \text{ m}
\]
Now, we can substitute the value of \( r \) into the volume formula. Using \( \pi \approx 3.14 \):
\[
V = \frac{4}{3} \times 3.14 \times (9.4)^3
\]
First, calculate \( (9.4)^3 \):
\[
9.4^3 = 9.4 \times 9.4 \times 9.4 = 830.584
\]
Now, substitute \( 9.4^3 \) into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 830.584
\]
Next, calculate \( \frac{4}{3} \times 3.14 \):
\[
\frac{4}{3} \times 3.14 \approx 4.18666667 \text{ (approximately 4.19)}
\]
Now, continue calculating the volume:
\[
V \approx 4.18666667 \times 830.584 \approx 3477.797
\]
Finally, round this value to the nearest tenth:
\[
V \approx 3477.8 \, \text{m}^3
\]
Therefore, the volume of the sphere is approximately:
\[
\boxed{3477.8 \, \text{m}^3}
\]