Question
If 120g of Calcium Oxide is added to 90g of Carbon Dioxide, the result is Calcium Carbonate. What is the correct estimate of the amount of Calcium Carbonate?
Group of answer choices
210g (sum of 120g and 90g)
30g (difference of 120g and 90g)
Twice the sum of 120g and 90g
Twice the difference of 120g and 90g
Group of answer choices
210g (sum of 120g and 90g)
30g (difference of 120g and 90g)
Twice the sum of 120g and 90g
Twice the difference of 120g and 90g
Answers
GPT-4o mini
To determine the amount of Calcium Carbonate (CaCO₃) produced from the reaction of Calcium Oxide (CaO) and Carbon Dioxide (CO₂), we can start by looking at the balanced chemical equation for the reaction:
\[ \text{CaO} + \text{CO}_2 \rightarrow \text{CaCO}_3 \]
In this reaction, one mole of calcium oxide reacts with one mole of carbon dioxide to produce one mole of calcium carbonate. Therefore, the mass of calcium carbonate produced will be the sum of the masses of the two reactants.
Given the masses:
- Mass of Calcium Oxide (CaO) = 120g
- Mass of Carbon Dioxide (CO₂) = 90g
The total mass of the products will be the sum of the masses of the reactants:
\[ 120 \text{g (CaO)} + 90 \text{g (CO₂)} = 210 \text{g (CaCO}_3\text{)} \]
Thus, the correct estimate of the amount of Calcium Carbonate produced is **210g**.
Therefore, the answer is:
**210g (sum of 120g and 90g)**.
\[ \text{CaO} + \text{CO}_2 \rightarrow \text{CaCO}_3 \]
In this reaction, one mole of calcium oxide reacts with one mole of carbon dioxide to produce one mole of calcium carbonate. Therefore, the mass of calcium carbonate produced will be the sum of the masses of the two reactants.
Given the masses:
- Mass of Calcium Oxide (CaO) = 120g
- Mass of Carbon Dioxide (CO₂) = 90g
The total mass of the products will be the sum of the masses of the reactants:
\[ 120 \text{g (CaO)} + 90 \text{g (CO₂)} = 210 \text{g (CaCO}_3\text{)} \]
Thus, the correct estimate of the amount of Calcium Carbonate produced is **210g**.
Therefore, the answer is:
**210g (sum of 120g and 90g)**.
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