Question
A rectangular park has area of 1.36 x10^8 ft squared
Answers
Answered by
GPT-4o mini
To analyze the area of the rectangular park, let's break it down a bit. The area is given as \( 1.36 \times 10^8 \) square feet.
To find the length and width of the rectangular park, we need additional information such as the ratio of the length to the width or either dimension.
However, if you want to express the dimensions based on a specific choice for one of the sides, here are some possibilities:
1. **Assuming a square park**: If the park were square, both the length and width would be the square root of the area.
\[
\text{Side} = \sqrt{1.36 \times 10^8} \approx 11680 \, \text{ft}
\]
(since \( 11680^2 \approx 1.36 \times 10^8 \)).
2. **Different aspect ratios**: If you have a preferred ratio (for instance, 2:1), you could let the length \( l \) be \( 2w \) (width) and set up the equation:
\[
l \times w = 1.36 \times 10^8
\]
Substituting \( l = 2w \):
\[
2w \times w = 1.36 \times 10^8 \implies 2w^2 = 1.36 \times 10^8 \implies w^2 = 68000000 \implies w \approx 8164 \, \text{ft}, \, l \approx 16328 \, \text{ft}
\]
3. **More specific details**: If you have other specifications in mind—such as perimeter limits or a fixed one side—please provide that, and I can calculate more specific dimensions accordingly.
Feel free to specify any further details or questions regarding this park!
To find the length and width of the rectangular park, we need additional information such as the ratio of the length to the width or either dimension.
However, if you want to express the dimensions based on a specific choice for one of the sides, here are some possibilities:
1. **Assuming a square park**: If the park were square, both the length and width would be the square root of the area.
\[
\text{Side} = \sqrt{1.36 \times 10^8} \approx 11680 \, \text{ft}
\]
(since \( 11680^2 \approx 1.36 \times 10^8 \)).
2. **Different aspect ratios**: If you have a preferred ratio (for instance, 2:1), you could let the length \( l \) be \( 2w \) (width) and set up the equation:
\[
l \times w = 1.36 \times 10^8
\]
Substituting \( l = 2w \):
\[
2w \times w = 1.36 \times 10^8 \implies 2w^2 = 1.36 \times 10^8 \implies w^2 = 68000000 \implies w \approx 8164 \, \text{ft}, \, l \approx 16328 \, \text{ft}
\]
3. **More specific details**: If you have other specifications in mind—such as perimeter limits or a fixed one side—please provide that, and I can calculate more specific dimensions accordingly.
Feel free to specify any further details or questions regarding this park!