The height y (in feet) of a ball thrown by a child is y=-1/14 x squared + 6x+5

Where x is the horizontal distance in feet from the point at which the ball is thrown.
How high is the ball when it leaves the child’s hand?
What is the maximum height of the ball?
How far from the child does the ball strike the ground?

1 answer

To analyze the height function of the ball given by \( y = -\frac{1}{14}x^2 + 6x + 5 \), we will answer the three questions step by step.

1. Height when the ball leaves the child's hand:

To find the height when the ball leaves the child's hand, we evaluate \( y \) at \( x = 0 \):

\[ y(0) = -\frac{1}{14}(0)^2 + 6(0) + 5 = 5 \]

The height of the ball when it leaves the child's hand is 5 feet.

2. Maximum height of the ball:

The given quadratic function \( y = -\frac{1}{14}x^2 + 6x + 5 \) is a downward-opening parabola, and its maximum height can be found at the vertex.

The x-coordinate of the vertex can be calculated using the formula \( x = -\frac{b}{2a} \), where \( a = -\frac{1}{14} \) and \( b = 6 \):

\[ x = -\frac{6}{2 \cdot -\frac{1}{14}} = -\frac{6}{-\frac{1}{7}} = 6 \cdot 7 = 42 \]

Now, substitute \( x = 42 \) back into the function to find the maximum height:

\[ y(42) = -\frac{1}{14}(42)^2 + 6(42) + 5 \]

Calculating each term:

  1. \( -\frac{1}{14}(42)^2 = -\frac{1}{14} \cdot 1764 = -126 \)
  2. \( 6(42) = 252 \)
  3. Therefore, \[ y(42) = -126 + 252 + 5 = 126 + 5 = 131 \]

The maximum height of the ball is 131 feet.

3. How far from the child does the ball strike the ground?

The ball strikes the ground when \( y = 0 \). We set the height function equal to zero and solve for \( x \):

\[ -\frac{1}{14}x^2 + 6x + 5 = 0 \]

To eliminate the fraction, multiply through by -14:

\[ x^2 - 84x - 70 = 0 \]

Now, we will use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \):

Here, \( a = 1 \), \( b = -84 \), and \( c = -70 \):

  1. Calculate the discriminant:

\[ b^2 - 4ac = (-84)^2 - 4(1)(-70) = 7056 + 280 = 7336 \]

  1. Apply the quadratic formula:

\[ x = \frac{84 \pm \sqrt{7336}}{2} \]

Calculate \( \sqrt{7336} \):

\[ \sqrt{7336} \approx 85.7 \]

Now plug it into the formula:

\[ x \approx \frac{84 \pm 85.7}{2} \]

Calculate both possible \( x \) values:

  1. \( x_1 = \frac{169.7}{2} \approx 84.85 \)
  2. \( x_2 = \frac{-1.7}{2} \) (which we discard as \( x \) cannot be negative)

The ball strikes the ground approximately 84.85 feet from the child.

Summary of Results:

  • Height when the ball leaves the child's hand: 5 feet
  • Maximum height of the ball: 131 feet
  • Distance from the child when the ball strikes the ground: approximately 84.85 feet