Asked by r
Which expression is equivalent to square root of 32x^6 ?
A. 4x^3 square root of 2
B. 8x^3
C. 4x square root of 2
D. 16x^3
A. 4x^3 square root of 2
B. 8x^3
C. 4x square root of 2
D. 16x^3
Answers
Answered by
GPT-4o mini
To simplify the expression \(\sqrt{32x^6}\), we can break it down as follows:
1. **Simplify the constant**:
\[
32 = 16 \times 2 = 4^2 \times 2
\]
Thus,
\[
\sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \times \sqrt{2} = 4\sqrt{2}
\]
2. **Simplify the variable**:
When simplifying \(\sqrt{x^6}\), we can use the property that \(\sqrt{x^n} = x^{n/2}\):
\[
\sqrt{x^6} = x^{6/2} = x^3
\]
3. **Combine the results**:
Therefore, we have:
\[
\sqrt{32x^6} = \sqrt{32} \times \sqrt{x^6} = (4\sqrt{2}) \times (x^3) = 4x^3\sqrt{2}
\]
So, the equivalent expression is **A. \(4x^3\sqrt{2}\)**.
1. **Simplify the constant**:
\[
32 = 16 \times 2 = 4^2 \times 2
\]
Thus,
\[
\sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \times \sqrt{2} = 4\sqrt{2}
\]
2. **Simplify the variable**:
When simplifying \(\sqrt{x^6}\), we can use the property that \(\sqrt{x^n} = x^{n/2}\):
\[
\sqrt{x^6} = x^{6/2} = x^3
\]
3. **Combine the results**:
Therefore, we have:
\[
\sqrt{32x^6} = \sqrt{32} \times \sqrt{x^6} = (4\sqrt{2}) \times (x^3) = 4x^3\sqrt{2}
\]
So, the equivalent expression is **A. \(4x^3\sqrt{2}\)**.
Answered by
r
are you positive
Answered by
GPT-4o mini
Yes, I'm confident in my previous calculations. Let's recap the simplification of \(\sqrt{32x^6}\) to verify:
1. **Calculate the square root of the constant**:
- \(32\) can be expressed as \(16 \times 2\).
- Thus, \(\sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \times \sqrt{2} = 4\sqrt{2}\).
2. **Calculate the square root of the variable**:
- For \(x^6\), we apply the property of square roots: \(\sqrt{x^n} = x^{n/2}\).
- So, \(\sqrt{x^6} = x^{6/2} = x^3\).
3. **Combine both results**:
- Now we combine the results:
\[
\sqrt{32x^6} = \sqrt{32} \times \sqrt{x^6} = (4\sqrt{2}) \times (x^3) = 4x^3\sqrt{2}.
\]
Thus, the expression \(\sqrt{32x^6}\) simplifies to \(4x^3\sqrt{2}\), confirming that the answer is indeed **A. \(4x^3\sqrt{2}\)**.
1. **Calculate the square root of the constant**:
- \(32\) can be expressed as \(16 \times 2\).
- Thus, \(\sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \times \sqrt{2} = 4\sqrt{2}\).
2. **Calculate the square root of the variable**:
- For \(x^6\), we apply the property of square roots: \(\sqrt{x^n} = x^{n/2}\).
- So, \(\sqrt{x^6} = x^{6/2} = x^3\).
3. **Combine both results**:
- Now we combine the results:
\[
\sqrt{32x^6} = \sqrt{32} \times \sqrt{x^6} = (4\sqrt{2}) \times (x^3) = 4x^3\sqrt{2}.
\]
Thus, the expression \(\sqrt{32x^6}\) simplifies to \(4x^3\sqrt{2}\), confirming that the answer is indeed **A. \(4x^3\sqrt{2}\)**.