Question

A University football stadium has 81,500 seats the stadium is at full capacity on game day Layla believes only $79,000 seats were occupied find the percent error of latest prediction run your answer to the nearest hundredth of a percent a 3.07% b 90.3067% see -3.07% d 0.0307%

Answer 1

To calculate the percent error of Layla's prediction, we can use the following formula for percent error:

\[
\text{Percent Error} = \left( \frac{\text{Estimated Value} - \text{Actual Value}}{\text{Actual Value}} \right) \times 100
\]

In this case:

- Estimated Value (Layla's prediction) = 79,000
- Actual Value (total seats) = 81,500

Using the formula, we can plug in the numbers:

\[
\text{Percent Error} = \left( \frac{79,000 - 81,500}{81,500} \right) \times 100
\]

First, calculate the difference:

\[
79,000 - 81,500 = -2,500
\]

Now, plug this back into the formula:

\[
\text{Percent Error} = \left( \frac{-2,500}{81,500} \right) \times 100
\]

Calculating the division:

\[
\frac{-2,500}{81,500} \approx -0.0307
\]

Now multiply by 100 to find the percentage:

\[
\text{Percent Error} \approx -0.0307 \times 100 \approx -3.07\%
\]

Rounding to the nearest hundredth of a percent, the percent error is \(-3.07\%\).

Thus, the correct answer is **c. -3.07%**.