Asked by anony
A human gene carries a certain disease from the mother to the child with a probability rate of 53%. That is,
there is a 53% chance that the child becomes infected with the disease. Suppose a female carrier of the gene has
three children. Assume that the infections of the three children are independent of one another. Find the
probability that all three of the children get the disease from their mother.
I don't really need an answer persay. I am trying to figure out a formula or how to figure out this problem for the most part because I am confused!
there is a 53% chance that the child becomes infected with the disease. Suppose a female carrier of the gene has
three children. Assume that the infections of the three children are independent of one another. Find the
probability that all three of the children get the disease from their mother.
I don't really need an answer persay. I am trying to figure out a formula or how to figure out this problem for the most part because I am confused!
Answers
Answered by
bobpursley
pr= .53*.53*.53
Answered by
Abdinajib
mother wants to divide $680.00 among her children according to the ratio 2:4:6. The shares would be
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