It takes 1 molecule of nitrogen and 3

molecules of hydrogen to produce 2
molecules of ammonia using the following formula:

1N2+ 3H2 → 2NH3

Identify which combination of molecules will produce ammonia with no leftovers?

(1 point)
Responses

4N2 and 4H2
4 n sub 2 and 4 h sub 2

2N2 and 6H2
2 n sub 2 and 6 h sub 2

5N2 and 6H2
5 n sub 2 and 6 h sub 2

8N2 and 4H2
8 n sub 2 and 4 h sub 2
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1 answer

To determine which combination of molecules will produce ammonia with no leftovers, we need to analyze the stoichiometry of the reaction:

The balanced equation is: \[ 1N_2 + 3H_2 \rightarrow 2NH_3 \]

From the equation, we can see that:

  • 1 molecule of nitrogen (N₂) reacts with 3 molecules of hydrogen (H₂) to produce 2 molecules of ammonia (NH₃).

Now let's evaluate each option:

  1. 4N₂ and 4H₂:

    • From 4N₂, we can produce \(4 \times 2 = 8NH₃\).
    • This requires \(4 \times 3 = 12H₂\).
    • Not enough hydrogen, leftovers of N₂.
  2. 2N₂ and 6H₂:

    • From 2N₂, we can produce \(2 \times 2 = 4NH₃\).
    • This requires \(2 \times 3 = 6H₂\).
    • Perfectly used up, no leftovers.
  3. 5N₂ and 6H₂:

    • From 5N₂, we can produce \(5 \times 2 = 10NH₃\).
    • This requires \(5 \times 3 = 15H₂\).
    • Not enough hydrogen, leftovers of N₂.
  4. 8N₂ and 4H₂:

    • From 8N₂, we can produce \(8 \times 2 = 16NH₃\).
    • This requires \(8 \times 3 = 24H₂\).
    • Not enough hydrogen, leftovers of N₂.

The only combination that produces ammonia with no leftovers is:

2N₂ and 6H₂.