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While using zero product property to find the value of x that makes a quadologic equation x + 3 * x + 4 = 0 Oliver completed the work provided in the table is Oliver's work accurate no x minus 3 equals 0 in the second row should be x + 3 = 0 yes the work is

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To solve the quadratic equation \( (x + 3)(x + 4) = 0 \) using the zero product property, we first set each factor equal to zero:

  1. \( x + 3 = 0 \)
  2. \( x + 4 = 0 \)

Now we can solve each equation:

  1. For \( x + 3 = 0 \): \[ x = -3 \]

  2. For \( x + 4 = 0 \): \[ x = -4 \]

So the solutions to the equation \( (x + 3)(x + 4) = 0 \) are \( x = -3 \) and \( x = -4 \).

Regarding Oliver's work, if he wrote \( x - 3 = 0 \) in the second row instead of \( x + 3 = 0 \), then he made a mistake in identifying the factors of the equation. Hence, his work would not be accurate.

To summarize:

  • Yes, the correct factor to set equal to zero is \( x + 3 = 0 \), not \( x - 3 = 0 \).
  • Oliver's conclusion based on that mistake would not be accurate.

So to answer your question about whether Oliver's work is accurate: No, it is not accurate.