To calculate the total mass of the reactants in the reaction, we need to find the mass of each reactant and add them together.
The reaction is: \[ \text{FeCl}_3 + 3\text{H}_2\text{O} \]
Step 1: Calculate the mass of FeCl\(_3\):
- Iron (Fe): 1 atom with mass = 56 amu
- Chlorine (Cl): 3 atoms with mass = 3 × 35 amu = 105 amu
So, the total mass of FeCl\(_3\): \[ 56 \text{ amu} + 105 \text{ amu} = 161 \text{ amu} \]
Step 2: Calculate the mass of 3H\(_2\)O:
- Hydrogen (H): 2 atoms per molecule, and there are 3 water molecules, so total H = 3 × 2 = 6 atoms with mass = 6 × 1 amu = 6 amu
- Oxygen (O): 3 atoms with mass = 3 × 16 amu = 48 amu
So, the total mass of 3H\(_2\)O: \[ 6 \text{ amu} + 48 \text{ amu} = 54 \text{ amu} \]
Step 3: Calculate the total mass of the reactants: \[ \text{Total mass of reactants} = \text{Mass of FeCl}_3 + \text{Mass of } 3\text{H}_2\text{O} \] \[ \text{Total mass of reactants} = 161 \text{ amu} + 54 \text{ amu} = 215 \text{ amu} \]
Thus, the total mass of the reactants is 215 amu.