As the pressure of a gas decreases to half its original value, what happens to the volume of the gas if temperature is held constant?(1 point)

Responses

The volume decreases to half of its original value.
The volume decreases to half of its original value.

The volume increases to twice its original value.
The volume increases to twice its original value.

The volume decreases to one-fourth of its original value.
The volume decreases to one-fourth of its original value.

The volume increases to four times its original value.

1 answer

According to Boyle's Law, which states that for a given mass of gas at constant temperature, the pressure of the gas is inversely proportional to its volume. This can be expressed as \( P_1 V_1 = P_2 V_2 \).

If the pressure decreases to half of its original value (i.e., \( P_2 = \frac{1}{2} P_1 \)), we can set up the equation:

\[ P_1 V_1 = \left(\frac{1}{2} P_1\right) V_2 \]

By simplifying this equation, we find:

\[ V_2 = 2V_1 \]

This means that if the pressure of a gas decreases to half its original value while keeping the temperature constant, the volume of the gas will increase to twice its original value.

Therefore, the correct response is:

The volume increases to twice its original value.