Question
Jimmy reads 15 pages in 5 minutes. Carlo reads 12 pages in 6 minutes. Find each constant of proportionality, showing your work. Then write a sentence to compare the proportional relationships.(2 points)
make it sound like a 12 year old wrote it
make it sound like a 12 year old wrote it
Answers
GPT-4o mini
To find the constant of proportionality for both Jimmy and Carlo, we need to find out how many pages each of them reads in one minute.
**For Jimmy:**
He reads 15 pages in 5 minutes. To find out how many pages he reads in 1 minute, we can divide the total pages by the total minutes:
15 pages ÷ 5 minutes = 3 pages per minute.
So, the constant of proportionality for Jimmy is **3**.
**For Carlo:**
He reads 12 pages in 6 minutes. We'll do the same thing and divide the total pages by the total minutes:
12 pages ÷ 6 minutes = 2 pages per minute.
So, the constant of proportionality for Carlo is **2**.
**Comparison:**
Jimmy reads faster than Carlo because he reads 3 pages in a minute, while Carlo only reads 2 pages in a minute. It’s like how Jimmy zooms through his book way quicker!
**For Jimmy:**
He reads 15 pages in 5 minutes. To find out how many pages he reads in 1 minute, we can divide the total pages by the total minutes:
15 pages ÷ 5 minutes = 3 pages per minute.
So, the constant of proportionality for Jimmy is **3**.
**For Carlo:**
He reads 12 pages in 6 minutes. We'll do the same thing and divide the total pages by the total minutes:
12 pages ÷ 6 minutes = 2 pages per minute.
So, the constant of proportionality for Carlo is **2**.
**Comparison:**
Jimmy reads faster than Carlo because he reads 3 pages in a minute, while Carlo only reads 2 pages in a minute. It’s like how Jimmy zooms through his book way quicker!
The temperature is dropping throughout the day as a cold front comes in. In City A, the temperature is changing by −5°F
−
5
°
F
per hour, and in City B the temperature is changing by −3°F
−
3
°
F
per hour. If the temperatures in both cities started at 70°F
70
°
F
, which city is warmer, and what is the difference in their temperatures after 5 hours?(1 point)
Responses
City A is warmer by 2°F
2
°
F
.
City A is warmer by 2 degrees F .
City A is warmer by 10°F
10
°
F
.
City A is warmer by 10 degrees F .
City B is warmer by 2°F
2
°
F
.
City B is warmer by 2 degrees F .
City B is warmer by 10°F
10
°
F
.
−
5
°
F
per hour, and in City B the temperature is changing by −3°F
−
3
°
F
per hour. If the temperatures in both cities started at 70°F
70
°
F
, which city is warmer, and what is the difference in their temperatures after 5 hours?(1 point)
Responses
City A is warmer by 2°F
2
°
F
.
City A is warmer by 2 degrees F .
City A is warmer by 10°F
10
°
F
.
City A is warmer by 10 degrees F .
City B is warmer by 2°F
2
°
F
.
City B is warmer by 2 degrees F .
City B is warmer by 10°F
10
°
F
.
GPT-4o mini
To find out which city is warmer and the difference in their temperatures after 5 hours, we need to calculate the temperature in each city after that time.
**For City A:**
- Initial temperature: 70°F
- Rate of change: -5°F per hour
- Time: 5 hours
Temperature in City A after 5 hours = Initial temperature + (Rate of change × Time)
Temperature in City A after 5 hours = 70°F + (-5°F/hour × 5 hours)
Temperature in City A after 5 hours = 70°F - 25°F = 45°F
**For City B:**
- Initial temperature: 70°F
- Rate of change: -3°F per hour
- Time: 5 hours
Temperature in City B after 5 hours = Initial temperature + (Rate of change × Time)
Temperature in City B after 5 hours = 70°F + (-3°F/hour × 5 hours)
Temperature in City B after 5 hours = 70°F - 15°F = 55°F
**Comparison:**
- Temperature in City A after 5 hours: 45°F
- Temperature in City B after 5 hours: 55°F
Now we see that City B is warmer than City A.
To find the difference in temperatures:
Difference = Temperature in City B - Temperature in City A
Difference = 55°F - 45°F = 10°F
So, the answer is:
**City B is warmer by 10°F.**
**For City A:**
- Initial temperature: 70°F
- Rate of change: -5°F per hour
- Time: 5 hours
Temperature in City A after 5 hours = Initial temperature + (Rate of change × Time)
Temperature in City A after 5 hours = 70°F + (-5°F/hour × 5 hours)
Temperature in City A after 5 hours = 70°F - 25°F = 45°F
**For City B:**
- Initial temperature: 70°F
- Rate of change: -3°F per hour
- Time: 5 hours
Temperature in City B after 5 hours = Initial temperature + (Rate of change × Time)
Temperature in City B after 5 hours = 70°F + (-3°F/hour × 5 hours)
Temperature in City B after 5 hours = 70°F - 15°F = 55°F
**Comparison:**
- Temperature in City A after 5 hours: 45°F
- Temperature in City B after 5 hours: 55°F
Now we see that City B is warmer than City A.
To find the difference in temperatures:
Difference = Temperature in City B - Temperature in City A
Difference = 55°F - 45°F = 10°F
So, the answer is:
**City B is warmer by 10°F.**
Which of these objects would reach 100 feet in the least amount of time?
(1 point)
Responses
They would all reach 100 feet at the same time.
They would all reach 100 feet at the same time.
object A
object A
object C
object C
object B
(1 point)
Responses
They would all reach 100 feet at the same time.
They would all reach 100 feet at the same time.
object A
object A
object C
object C
object B
GPT-4o mini
To determine which object would reach 100 feet in the least amount of time, we would typically need information about the speed or acceleration of each object. Since you haven't provided specific details about these objects (like their speeds, weights, or whether they are being dropped, thrown, etc.), I can't definitively say which one would reach 100 feet first.
If all objects are dropped from the same height (assuming they are in free fall and neglecting air resistance), they would all reach the ground at the same time. However, if they are moving at different speeds or have other factors influencing their motion, the one with the highest speed or acceleration would reach 100 feet first.
So based on common scenarios:
- If they are simply falling freely, **they would all reach 100 feet at the same time.**
- If one of them is being projected or thrown upwards faster than the others, that one might reach 100 feet quicker.
If you have specific details about each object, let me know, and I can help you determine which one would reach 100 feet the fastest!
If all objects are dropped from the same height (assuming they are in free fall and neglecting air resistance), they would all reach the ground at the same time. However, if they are moving at different speeds or have other factors influencing their motion, the one with the highest speed or acceleration would reach 100 feet first.
So based on common scenarios:
- If they are simply falling freely, **they would all reach 100 feet at the same time.**
- If one of them is being projected or thrown upwards faster than the others, that one might reach 100 feet quicker.
If you have specific details about each object, let me know, and I can help you determine which one would reach 100 feet the fastest!
just the answer
GPT-4o mini
They would all reach 100 feet at the same time.
A whale swims 200 miles in 5 days. Identify which equation could be used to find how many miles it swims in 16 days.(1 point)
Responses
y=200×16×5
𝑦
=
200
×
16
×
5
y equals 200 times 16 times 5
200=16x
200
=
16
𝑥
200 equals 16 x
y=40×16
𝑦
=
40
×
16
y equals 40 times 16
y=200×16
Responses
y=200×16×5
𝑦
=
200
×
16
×
5
y equals 200 times 16 times 5
200=16x
200
=
16
𝑥
200 equals 16 x
y=40×16
𝑦
=
40
×
16
y equals 40 times 16
y=200×16
GPT-4o mini
The correct equation to find how many miles the whale swims in 16 days is:
**y = 40 × 16**
This is because the whale swims at a rate of 40 miles per day (200 miles ÷ 5 days = 40 miles per day).
**y = 40 × 16**
This is because the whale swims at a rate of 40 miles per day (200 miles ÷ 5 days = 40 miles per day).