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Use the unbalanced chemical equation to answer the question. 2NaHCO3 → Na2CO3 + CO2 Which of the following can be added to the...Asked by Noo
Use the unbalanced chemical equation to answer the question.
2NaHCO → Na, CO + CO2
Which of the following can be added to the products to balance the equation?
(1 point)
002
0H20
O H2
CH,OH
2NaHCO → Na, CO + CO2
Which of the following can be added to the products to balance the equation?
(1 point)
002
0H20
O H2
CH,OH
Answers
Answered by
GPT-4o mini
To balance the unbalanced equation given as:
\[ 2 \text{NaHCO} \rightarrow \text{Na} + \text{CO} + \text{CO}_2 \]
We need to balance the number of each type of atom on both sides of the equation.
Currently on the product side, the left side has:
- Sodium (Na): 2 from 2NaHCO
- Carbon (C): 2 from 2NaHCO
- Oxygen (O): 6 from 2NaHCO (O in HCO)
On the right side:
- Sodium (Na): 1
- Carbon (C): 2 (1 from CO and 1 from CO₂)
- Oxygen (O): 3 (2 from CO₂ and 1 from CO)
To balance the sodium, you would need 2 Na on the products side.
The correct balancing process shows that there is also a need to adjust the oxygen count.
However, looking at the options you provided:
- **CO₂**: This adds carbon and oxygen but does not help balance sodium.
- **H₂O**: This introduces more hydrogen and oxygen.
- **H₂**: This does not help as it introduces more hydrogen without addressing carbon or sodium.
- **CH₃OH**: This introduces more carbon, oxygen, and hydrogen.
None of these options directly balance the equation as initially proposed. However, adding more products or reactants along with completing balancing operations might eventually lead to the correct balanced equation:
\[
2 \text{NaHCO}_3 \rightarrow 2 \text{Na} + \text{2CO} + \text{H}_2\text{O} + \text{CO}_2
\]
This implies that given the options provided with consideration of standard reactions, **CO₂** could be a reasonable choice for balancing purposes since CO₂ is already part of the product side and accounting for it could aid in achieving a balance.
Therefore, if the goal is to balance the chemical equation you've provided, adding **CO₂** could be seen as a strategic choice given what products you have.
However, since the equation in its initial state was written incorrectly, please confirm if you meant to add more context or reactants/products for an accurate chemical balancing situation.
\[ 2 \text{NaHCO} \rightarrow \text{Na} + \text{CO} + \text{CO}_2 \]
We need to balance the number of each type of atom on both sides of the equation.
Currently on the product side, the left side has:
- Sodium (Na): 2 from 2NaHCO
- Carbon (C): 2 from 2NaHCO
- Oxygen (O): 6 from 2NaHCO (O in HCO)
On the right side:
- Sodium (Na): 1
- Carbon (C): 2 (1 from CO and 1 from CO₂)
- Oxygen (O): 3 (2 from CO₂ and 1 from CO)
To balance the sodium, you would need 2 Na on the products side.
The correct balancing process shows that there is also a need to adjust the oxygen count.
However, looking at the options you provided:
- **CO₂**: This adds carbon and oxygen but does not help balance sodium.
- **H₂O**: This introduces more hydrogen and oxygen.
- **H₂**: This does not help as it introduces more hydrogen without addressing carbon or sodium.
- **CH₃OH**: This introduces more carbon, oxygen, and hydrogen.
None of these options directly balance the equation as initially proposed. However, adding more products or reactants along with completing balancing operations might eventually lead to the correct balanced equation:
\[
2 \text{NaHCO}_3 \rightarrow 2 \text{Na} + \text{2CO} + \text{H}_2\text{O} + \text{CO}_2
\]
This implies that given the options provided with consideration of standard reactions, **CO₂** could be a reasonable choice for balancing purposes since CO₂ is already part of the product side and accounting for it could aid in achieving a balance.
Therefore, if the goal is to balance the chemical equation you've provided, adding **CO₂** could be seen as a strategic choice given what products you have.
However, since the equation in its initial state was written incorrectly, please confirm if you meant to add more context or reactants/products for an accurate chemical balancing situation.
Answered by
GPT-4o mini
To balance the equation:
\[ 2 \text{NaHCO}_3 \rightarrow 2 \text{Na} + \text{2CO} + \text{CO}_2 + \text{H}_2\text{O} \]
Of the provided options, you can add **CO₂** to help balance the equation. This is because there is already carbon being produced, and adding CO₂ can assist in achieving a proper balance of atoms.
Therefore, the correct answer is:
**CO₂**.
\[ 2 \text{NaHCO}_3 \rightarrow 2 \text{Na} + \text{2CO} + \text{CO}_2 + \text{H}_2\text{O} \]
Of the provided options, you can add **CO₂** to help balance the equation. This is because there is already carbon being produced, and adding CO₂ can assist in achieving a proper balance of atoms.
Therefore, the correct answer is:
**CO₂**.
Answered by
GPT-4o mini
To balance the given unbalanced chemical equation:
\[ 2 \text{NaHCO}_3 \rightarrow \text{Na}_2\text{CO}_3 + \text{CO}_2 \]
Let's break down the reactants and products regarding the number of each atom.
**On the left side (reactants):**
- Sodium (Na): 2 (from 2NaHCO3)
- Carbon (C): 2 (from 2NaHCO3)
- Oxygen (O): 6 (from 2NaHCO3 which has 3 oxygen atoms from each NaHCO3)
**On the right side (products):**
- Sodium (Na): 2 (from Na₂CO₃)
- Carbon (C): 2 (1 from Na₂CO₃ and 1 from CO₂)
- Oxygen (O): 5 (3 from Na₂CO₃ and 2 from CO₂)
The oxygen is unbalanced, as the left side has 6 and the right side has 5.
The options you provided are:
1. **O₂** - adding O₂ would add more oxygen but won't balance the equation as we need to account for different elements.
2. **H₂O** - adding H₂O to the products will introduce hydrogen and oxygen, which can help with the balancing overall.
3. **H₂** - adding H₂ wouldn't help in balancing the equation as we don't have any H in the reactants.
To balance the oxygen, the correct choice would be to add **H₂O** to the products side to ensure that we achieve the same number of oxygen atoms on both sides.
So, the correct answer is:
**H₂O**.
\[ 2 \text{NaHCO}_3 \rightarrow \text{Na}_2\text{CO}_3 + \text{CO}_2 \]
Let's break down the reactants and products regarding the number of each atom.
**On the left side (reactants):**
- Sodium (Na): 2 (from 2NaHCO3)
- Carbon (C): 2 (from 2NaHCO3)
- Oxygen (O): 6 (from 2NaHCO3 which has 3 oxygen atoms from each NaHCO3)
**On the right side (products):**
- Sodium (Na): 2 (from Na₂CO₃)
- Carbon (C): 2 (1 from Na₂CO₃ and 1 from CO₂)
- Oxygen (O): 5 (3 from Na₂CO₃ and 2 from CO₂)
The oxygen is unbalanced, as the left side has 6 and the right side has 5.
The options you provided are:
1. **O₂** - adding O₂ would add more oxygen but won't balance the equation as we need to account for different elements.
2. **H₂O** - adding H₂O to the products will introduce hydrogen and oxygen, which can help with the balancing overall.
3. **H₂** - adding H₂ wouldn't help in balancing the equation as we don't have any H in the reactants.
To balance the oxygen, the correct choice would be to add **H₂O** to the products side to ensure that we achieve the same number of oxygen atoms on both sides.
So, the correct answer is:
**H₂O**.