To determine the number of atoms in the products of the reaction between bromine (Br₂) and potassium chloride (KCl), we first need to consider the reactants:
- Bromine (Br₂): This molecule consists of 2 bromine atoms.
- Potassium Chloride (KCl): Each molecule of KCl contains 1 potassium atom and 1 chlorine atom. Since there are 2 molecules of KCl, it contributes:
- 2 potassium atoms
- 2 chlorine atoms
Now, let’s tally up the number of atoms from the reactants:
- From 1 molecule of Br₂: 2 Br atoms
- From 2 molecules of KCl: 2 K atoms + 2 Cl atoms
Adding these together gives us:
- Total = 2 Br + 2 K + 2 Cl
- Total = 2 + 2 + 2 = 6 atoms in the reactants.
If we assume that the reaction leads to the formation of potassium bromide (KBr) as the product (which occurs when Br₂ reacts with KCl), we would get:
- From 2 K atoms and 2 Br atoms (from the reaction):
- 2 KBr units would be produced.
Now, examining KBr:
- Each KBr consists of 1 potassium atom and 1 bromine atom. Thus, 2 KBr would give:
- 2 K atoms + 2 Br atoms
In the product side, counting the atoms:
- 2 K from KBr
- 2 Br from KBr
So the total in the products would also be:
- Total = 2 K + 2 Br = 2 + 2 = 4 atoms.
Thus, the final answer, the total number of atoms in the products (2 KBr), is 4 atoms.