To determine which point is a solution to the simultaneous inequalities \( y > 3x + 1 \) and \( y \leq 2x + 5 \), we need to evaluate each point against both inequalities.
-
For the inequality \( y > 3x + 1 \):
- To check if a point \( (x, y) \) is a solution, we substitute \( x \) into the inequality and see if \( y \) is greater than \( 3x + 1 \).
-
For the inequality \( y \leq 2x + 5 \):
- Similarly, to check this inequality, we substitute \( x \) into the inequality and see if \( y \) is less than or equal to \( 2x + 5 \).
Since I don't have access to the image, you would need to evaluate each point by substituting the coordinates into both inequalities to find which point satisfies both conditions.
Please provide me with the coordinates of the points in the graph, and I can help you determine which one satisfies both inequalities!