It seems you're trying to describe a linear function based on some plotted points. However, the coordinates you've provided are a bit unclear, especially the way you've formatted them. I’ll interpret your description as two points on the Cartesian plane:
- Point \( Y \) (which I assume means a point on the graph) is at \( (12, 11) \).
- Point \( X \) is at \( (-3, -4) \).
If these are indeed the two points on the graph, we can find the equation of the linear function that passes through these two points.
The general form of a line is:
\[ y = mx + b \]
Where \( m \) is the slope. To find the slope \( m \), we can use the formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Substituting the values:
- \( (x_1, y_1) = (-3, -4) \)
- \( (x_2, y_2) = (12, 11) \)
Calculating the slope:
\[ m = \frac{11 - (-4)}{12 - (-3)} = \frac{11 + 4}{12 + 3} = \frac{15}{15} = 1 \]
Now, we know the slope \( m = 1 \).
Next, we can use one of the points to solve for \( b \). We'll use point \( (12, 11) \):
\[ y = mx + b \ 11 = 1 \cdot 12 + b \ 11 = 12 + b \ b = 11 - 12 = -1 \]
So, the equation of the linear function is:
\[ y = 1x - 1 \quad \text{or simply} \quad y = x - 1 \]
If this interpretation isn't what you were looking for, please clarify the points and their coordinates, and I'll be happy to assist further!