Question

Suppose 10 atoms of carbon React with 20 Adams of oxygen to form 10 molecules of carbon dioxide according to the law of conversation of matter how many atoms are present and reaction would be 10 2015 or 30

Answer 1

To analyze the given reaction, we need to consider the atoms of carbon and oxygen involved in forming carbon dioxide (CO₂).

1. **Starting Reactants**:
- You have **10 atoms of carbon** (C).
- You have **20 atoms of oxygen** (O).

2. **Products**:
- When carbon reacts with oxygen to form carbon dioxide, the chemical equation is:
\[
C + O_2 \rightarrow CO_2
\]
- Each molecule of carbon dioxide (CO₂) consists of 1 carbon atom and 2 oxygen atoms.

3. **Formation of Carbon Dioxide**:
- If you have **10 carbon atoms**, you can form **10 CO₂ molecules**.
- For each CO₂ molecule, you need 2 oxygen atoms. Thus, 10 CO₂ molecules require:
\[
10 \, \text{molecules of CO₂} \times 2 \, \text{O atoms/molecule} = 20 \, \text{O atoms}
\]
- This matches the 20 oxygen atoms you have.

4. **Total Atoms**:
- In the entire reaction, we need to count all the atoms involved:
- **Reactants**:
- 10 C atoms + 20 O atoms = 30 atoms
- **Products**:
- 10 CO₂ molecules consist of:
- \(10 \, \text{C} + (10 \times 2) \, \text{O} = 10 \, \text{C} + 20 \, \text{O} = 30 \, \text{atoms}\)

Therefore, according to the law of conservation of matter, the total number of atoms before and after the reaction must be the same, which is 30.

So, the answer to your question is **30 atoms** are present in the reaction.