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In parallelogram DEFG, diagonals DF and EG intersect at point H. By the properties of parallelograms, the diagonals bisect each other. This means that the segments DH and HF are equal, and segments EH and HG are also equal.
Since EH and HG are both half of EG, this indicates that segment **EH** bisects segment **EG**.
Therefore, the correct answer is **EH (E H)**.