Question
A cylinder is placed on the ground the cylinder has a weight of 85 newtons and has a radius of 2 cm work out the pressure on the ground in Newtons square meter
Answers
Answered by
GPT-4o mini
To calculate the pressure exerted by the cylinder on the ground, we can use the formula for pressure:
\[
\text{Pressure} = \frac{\text{Force}}{\text{Area}}
\]
In this case, the force is the weight of the cylinder, which is 85 newtons, and the area is the cross-sectional area of the cylinder in contact with the ground.
First, we need to calculate the area of the base of the cylinder. The formula for the area \(A\) of a circle is:
\[
A = \pi r^2
\]
where \(r\) is the radius of the circle. Given that the radius \(r\) is 2 cm, we need to convert this measurement to meters for consistency in units:
\[
r = 2 \text{ cm} = 0.02 \text{ m}
\]
Now, calculating the area:
\[
A = \pi (0.02)^2
\]
\[
A = \pi (0.0004) \approx 0.00125664 \text{ m}^2
\]
Now we can use the area to calculate the pressure:
\[
\text{Pressure} = \frac{85 \text{ N}}{0.00125664 \text{ m}^2} \approx 67681.84 \text{ N/m}^2
\]
Thus, the pressure exerted by the cylinder on the ground is approximately:
\[
\text{Pressure} \approx 67681.84 \text{ N/m}^2 \text{ (Pascals)}
\]
So, the answer is approximately 67681.84 Pascals.
\[
\text{Pressure} = \frac{\text{Force}}{\text{Area}}
\]
In this case, the force is the weight of the cylinder, which is 85 newtons, and the area is the cross-sectional area of the cylinder in contact with the ground.
First, we need to calculate the area of the base of the cylinder. The formula for the area \(A\) of a circle is:
\[
A = \pi r^2
\]
where \(r\) is the radius of the circle. Given that the radius \(r\) is 2 cm, we need to convert this measurement to meters for consistency in units:
\[
r = 2 \text{ cm} = 0.02 \text{ m}
\]
Now, calculating the area:
\[
A = \pi (0.02)^2
\]
\[
A = \pi (0.0004) \approx 0.00125664 \text{ m}^2
\]
Now we can use the area to calculate the pressure:
\[
\text{Pressure} = \frac{85 \text{ N}}{0.00125664 \text{ m}^2} \approx 67681.84 \text{ N/m}^2
\]
Thus, the pressure exerted by the cylinder on the ground is approximately:
\[
\text{Pressure} \approx 67681.84 \text{ N/m}^2 \text{ (Pascals)}
\]
So, the answer is approximately 67681.84 Pascals.
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