Determine whether the values −1 and 73 are solutions to the quadratic equation 3x2−4x−4=3.(1 point)

To determine if the values \(-1\) and \(73\) are solutions to the quadratic equation \(3x^2 - 4x - 4 = 3\), we first need to rearrange the equation into standard form by moving \(3\) to the left side:

\[
3x^2 - 4x - 4 - 3 = 0
\]
\[
3x^2 - 4x - 7 = 0
\]

Now we can substitute \(-1\) into the equation:

1. **Substituting \(x = -1\):**

\[
3(-1)^2 - 4(-1) - 7 = 0
\]
\[
3(1) + 4 - 7 = 0
\]
\[
3 + 4 - 7 = 0
\]
\[
0 = 0 \quad \text{(True)}
\]

Thus, \(-1\) is a solution to the equation.

2. **Substituting \(x = 73\):**

\[
3(73)^2 - 4(73) - 7 = 0
\]
Calculating \(73^2\):
\[
73^2 = 5329
\]
Now substitute:

\[
3(5329) - 4(73) - 7 = 0
\]
\[
15987 - 292 - 7 = 0
\]
Now perform the subtraction:

\[
15987 - 292 = 15695
\]
Then,

\[
15695 - 7 = 15688 \neq 0
\]

Thus, \(73\) is not a solution to the equation.

In conclusion:
- \(-1\) is a solution.
- \(73\) is not a solution.