To simplify the expression \(\frac{2x^3 - 2x}{x + 1}\), we first factor out the numerator:
\[ 2x^3 - 2x = 2x(x^2 - 1) = 2x(x - 1)(x + 1) \]
Thus, we can rewrite our expression:
\[ \frac{2x(x - 1)(x + 1)}{x + 1} \]
Now, we can cancel \((x + 1)\) from the numerator and the denominator (as long as \(x \neq -1\)):
\[ 2x(x - 1) \]
So, the simplified form of \(\frac{2x^3 - 2x}{x + 1}\) is:
\[ 2x(x - 1) = 2x^2 - 2x \]
Now, let's examine the provided options for an equivalent simplified form:
- \(2x^3 - 2x\) over \(x - 1\) - does not match.
- \(2x^3 + 2x^2 - 4x\) over \(x + 2\) - does not match.
- \(x^2 - 1\) over \(2x^2 + 2x\) - does not match.
- \(2x^2 + 6x\) over \(x^2 + 2x - 3\) - must check this one.
For the last option, we can simplify \(x^2 + 2x - 3\):
\[ x^2 + 2x - 3 = (x + 3)(x - 1) \]
So the expression can be written as:
\[ \frac{2x^2 + 6x}{(x + 3)(x - 1)} \]
However, simplifying \(2x^2 + 6x\) gives:
\[ 2x(x + 3) \]
Therefore, the overall expression looks like:
\[ \frac{2x(x + 3)}{(x + 3)(x - 1)} \]
If \(x + 3\) is not equal to zero (as long as \(x \neq -3\)), we can also cancel:
\[ \frac{2x}{x - 1} \]
None of the options simplify to the same expression as \(\frac{2x^2 - 2x}{1}\).
Thus, to conclude, the correct equivalent simplified expression of \(\frac{2x^3 - 2x}{x + 1}\) is not among the provided choices.