To find the total momentum of the three objects in the closed system before they collide, we add their momenta together:
- First object's momentum: \( 110 , \text{kg} \cdot \text{m/s} \)
- Second object's momentum: \( -65 , \text{kg} \cdot \text{m/s} \)
- Third object's momentum: \( -100 , \text{kg} \cdot \text{m/s} \)
Now, we sum these moments:
\[ \text{Total momentum} = 110 , \text{kg} \cdot \text{m/s} + (-65 , \text{kg} \cdot \text{m/s}) + (-100 , \text{kg} \cdot \text{m/s}) \]
Calculating this step by step:
\[ \text{Total momentum} = 110 - 65 - 100 \] \[ = 110 - 165 \] \[ = -55 , \text{kg} \cdot \text{m/s} \]
Thus, the total momentum after the collision, when the objects move together, is \( -55 , \text{kg} \cdot \text{m/s} \).
The correct response is:
−55 kg⋅m/s (negative 55 kilograms times meters per second)