To determine which linear equation has the same solution set as the given equation \(9d + 3 - 2d = -2(3 + d)\), we will first simplify the given equation.
Starting with the equation:
\[
9d + 3 - 2d = -2(3 + d)
\]
First, simplify the left-hand side:
\[
(9d - 2d) + 3 = 7d + 3
\]
Now simplify the right-hand side:
\[
-2(3 + d) = -6 - 2d
\]
Now we rewrite the equation:
\[
7d + 3 = -6 - 2d
\]
Next, isolate \(d\) by moving all \(d\) terms to one side and constant terms to the other:
\[
7d + 2d = -6 - 3
\]
\[
9d = -9
\]
\[
d = -1
\]
So the solution to the original equation is \(d = -1\).
Now we need to check which of the provided equations also has \(d = -1\) as a solution:
1. **Response 1:** \(35 - 15b = 95\)
This can be simplified:
\[
-15b = 95 - 35 \Rightarrow -15b = 60 \Rightarrow b = -4
\]
This does not have \(d = -1\) as a solution.
2. **Response 2:** \(4w - 2(7 - 3w) = \frac{w}{3} - 6\)
Simplify the left-hand side:
\[
4w - 14 + 6w = 10w - 14
\]
The right-hand side becomes:
\[
\frac{w}{3} - 6
\]
This doesn't lead to an easy isolation of a variable; let's check it later if needed.
3. **Response 3:** \(\frac{3x}{5} - 10 = -7\)
This can be simplified:
\[
\frac{3x}{5} = -7 + 10 \Rightarrow \frac{3x}{5} = 3
\]
\[
3x = 15 \Rightarrow x = 5
\]
The solution here is \(x = 5\) which doesn't match.
4. **Response 4:** \(14 = 74x - 194 + 2x\)
Rearranging gives:
\[
14 = 76x - 194
\]
\[
76x = 14 + 194 \Rightarrow 76x = 208 \Rightarrow x = \frac{208}{76} = \frac{52}{19}
\]
This does not match.
After checking all equations, it seems we must analyze the second one carefully to ensure it provides a solution of \(d = -1\).
Revisiting:
**Response 2:** \(4w - 2(7 - 3w) = \frac{w}{3} - 6\)
Expanding the left-hand side gives:
\[
4w - 14 + 6w = 10w - 14
\]
Set it equal to \(\frac{w}{3} - 6\). Multiply every term by 3 to clear the fraction:
\[
30w - 42 = w - 18
\]
Now, bringing the \(w\) terms together yields:
\[
30w - w = 42 - 18
\]
\[
29w = 24 \Rightarrow w = \frac{24}{29}
\]
Not the correct solution.
**Iteratively correcting away** other calculations — None match the solution sets.
In conclusion, the direct verification upon numeric adjustments shows none of the obtained equations equate to \(d = -1\) originally except clearly observing \glossary into further contextual identities shall map into solving better without blind requests.
None of the equations in the provided responses have the same solution set.