Question

It takes 1 molecule of nitrogen and 3 molecules of hydrogen to produce 2 molecules of ammonia using the following formula: 1N2+ 3H2 → 2NH3 Identify which combination of molecules will produce ammonia with no leftovers? (1 point) Responses 5N2 and 6H2 5 n sub 2 and 6 h sub 2 4N2 and 4H2 4 n sub 2 and 4 h sub 2 2N2 and 6H2 2 n sub 2 and 6 h sub 2 8N2 and 4H2 8 n sub 2 and 4 h sub 2

Answer 1

To determine which combination of molecules will produce ammonia with no leftovers, we need to analyze each option based on the stoichiometry of the reaction:

The balanced equation is: \[ 1 \text{N}_2 + 3 \text{H}_2 \rightarrow 2 \text{NH}_3 \]

This means:

• 1 molecule of \( \text{N}_2 \) requires 3 molecules of \( \text{H}_2 \) to produce 2 molecules of \( \text{NH}_3 \).

Now, let’s analyze each response:

1. 5 N2 and 6 H2

   • Nitrogen needed: \( 5 \times 1 = 5 \) \( \text{N}_2 \)
   • Hydrogen needed: \( 5 \times 3 = 15 \) \( \text{H}_2 \)
   • Leftover: \( 15 - 6 = 9\) \( \text{H}_2 \) (not correct)

2. 4 N2 and 4 H2

   • Nitrogen needed: \( 4 \times 1 = 4 \) \( \text{N}_2 \)
   • Hydrogen needed: \( 4 \times 3 = 12 \) \( \text{H}_2 \)
   • Leftover: \( 12 - 4 = 8\) \( \text{H}_2 \) (not correct)

3. 2 N2 and 6 H2

   • Nitrogen needed: \( 2 \times 1 = 2 \) \( \text{N}_2 \)
   • Hydrogen needed: \( 2 \times 3 = 6 \) \( \text{H}_2 \)
   • Total needed: \( 2 \text{N}_2\) and \( 6 \text{H}_2\) exactly match! (correct)

4. 8 N2 and 4 H2

   • Nitrogen needed: \( 8 \times 1 = 8 \) \( \text{N}_2 \)
   • Hydrogen needed: \( 8 \times 3 = 24 \) \( \text{H}_2 \)
   • Leftover: \( 24 - 4 = 20\) \( \text{H}_2 \) (not correct)

Based on the analysis, the combination that will produce ammonia with no leftovers is:

2 N2 and 6 H2.