Identify the vertex of y=−10(x+15)2−18.(1 point)

Question

Responses

(−10,−15)
left parenthesis negative 10 comma negative 15 right parenthesis

(15,−18)
left parenthesis 15 comma negative 18 right parenthesis

(−15,−18)
left parenthesis negative 15 comma negative 18 right parenthesis

(−150,−18)

Answer 1

The equation given is \(y = -10(x + 15)^2 - 18\).

This equation is in the vertex form of a quadratic equation, which is generally written as:

\[ y = a(x - h)^2 + k \]

where \((h, k)\) is the vertex of the parabola.

In the given equation:

• \(a = -10\)
• \((x + 15)\) can be rewritten as \((x - (-15))\), so \(h = -15\)
• \(k = -18\)

Thus, the vertex is \((-15, -18)\).

The correct answer is:

\((-15, -18)\)