According to the Law of Conservation of Mass, if 88 g of carbon dioxide ( CO2

) is produced in a reaction between oxygen (O) and 24 g of carbon (C), what is the mass of dioxygen ( O2
) in the reactants?(1 point)
Responses

24 g
24 g

64 g
64 g

32 g
32 g

104 g

1 answer

According to the Law of Conservation of Mass, the total mass of the reactants must equal the total mass of the products. In this case, we are given:

  • Mass of carbon (C) = 24 g
  • Mass of carbon dioxide produced (CO₂) = 88 g

To find the mass of dioxygen (O₂) in the reactants, we can set up the equation:

\[ \text{Mass of reactants} = \text{Mass of products} \] \[ \text{Mass of C} + \text{Mass of O₂} = \text{Mass of CO₂} \]

We can rearrange this to find the mass of O₂:

\[ \text{Mass of O₂} = \text{Mass of CO₂} - \text{Mass of C} \]

Substituting the given values:

\[ \text{Mass of O₂} = 88 , \text{g} - 24 , \text{g} = 64 , \text{g} \]

Therefore, the mass of dioxygen (O₂) in the reactants is 64 g.