To solve the quadratic equation \(2x^2 - 5x = 6\), we first rearrange it into standard form:
\[ 2x^2 - 5x - 6 = 0 \]
Next, we can use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 2\), \(b = -5\), and \(c = -6\).
First, we calculate the discriminant:
\[ b^2 - 4ac = (-5)^2 - 4(2)(-6) = 25 + 48 = 73 \]
Now we use the quadratic formula:
\[ x = \frac{-(-5) \pm \sqrt{73}}{2(2)} = \frac{5 \pm \sqrt{73}}{4} \]
Calculating \(\sqrt{73}\) gives approximately 8.54. Now we can substitute that back into the formula:
- For \(x = \frac{5 + \sqrt{73}}{4}\):
\[ x \approx \frac{5 + 8.54}{4} \approx \frac{13.54}{4} \approx 3.385 \]
- For \(x = \frac{5 - \sqrt{73}}{4}\):
\[ x \approx \frac{5 - 8.54}{4} \approx \frac{-3.54}{4} \approx -0.885 \]
Rounding this to the nearest hundredth gives us:
\[ x \approx -0.89 \]
Thus, the solution is:
\[ \text{x = -0.89} \]
So, the correct response is:
x = -0.89