A train is traveling at a velocity of 45 M/S to the east. One passenger is walking on the train. What is the passengers relative velocity to the ground if they are traveling 2 m/s to the east?

Answer 1

To find the passenger's relative velocity to the ground, you need to add the velocity of the train to the velocity of the passenger.

1. The velocity of the train is 45 m/s to the east.
2. The velocity of the passenger is 2 m/s to the east.

Since both velocities are in the same direction (to the east), you can simply add them together:

\[ \text{Relative velocity of the passenger to the ground} = \text{Velocity of the train} + \text{Velocity of the passenger} \]

\[ \text{Relative velocity of the passenger to the ground} = 45 , \text{m/s} + 2 , \text{m/s} = 47 , \text{m/s} \]

Therefore, the passenger's relative velocity to the ground is 47 m/s to the east.