Question
Finding the missing side of the right triangle. Round your answer to the nearest tenth. Click Here for Help Video.
222
191919
x=x=x=
70
Answers
Answer
The leg is 19 and the other leg is 2 we are trying to figure out the Hypotenuse which is x
Answered by
GPT-4o mini
To find the missing side of a right triangle, you can use the Pythagorean theorem, which states:
\[ a^2 + b^2 = c^2 \]
where \( c \) is the hypotenuse (the longest side of the triangle) and \( a \) and \( b \) are the other two sides.
From your input, it looks like we have a right triangle with:
- One side \( a = 70 \) (one of the legs)
- The hypotenuse \( c = 222 \)
We need to find the missing side \( b \).
Using the Pythagorean theorem:
\[ 70^2 + b^2 = 222^2 \]
Calculating \( 70^2 \) and \( 222^2 \):
\[ 70^2 = 4900 \]
\[ 222^2 = 49284 \]
Now substitute back into the equation:
\[ 4900 + b^2 = 49284 \]
Now solve for \( b^2 \):
\[ b^2 = 49284 - 4900 \]
\[ b^2 = 44384 \]
Now take the square root to find \( b \):
\[ b = \sqrt{44384} \]
Calculating the square root:
\[ b \approx 210.6 \]
So the length of the missing side \( b \) is approximately **210.6**.
\[ a^2 + b^2 = c^2 \]
where \( c \) is the hypotenuse (the longest side of the triangle) and \( a \) and \( b \) are the other two sides.
From your input, it looks like we have a right triangle with:
- One side \( a = 70 \) (one of the legs)
- The hypotenuse \( c = 222 \)
We need to find the missing side \( b \).
Using the Pythagorean theorem:
\[ 70^2 + b^2 = 222^2 \]
Calculating \( 70^2 \) and \( 222^2 \):
\[ 70^2 = 4900 \]
\[ 222^2 = 49284 \]
Now substitute back into the equation:
\[ 4900 + b^2 = 49284 \]
Now solve for \( b^2 \):
\[ b^2 = 49284 - 4900 \]
\[ b^2 = 44384 \]
Now take the square root to find \( b \):
\[ b = \sqrt{44384} \]
Calculating the square root:
\[ b \approx 210.6 \]
So the length of the missing side \( b \) is approximately **210.6**.
Answered by
GPT-4o mini
To find the hypotenuse \( x \) of a right triangle where the legs are \( a = 19 \) and \( b = 2 \), we can again use the Pythagorean theorem:
\[
a^2 + b^2 = c^2
\]
In this case, \( c \) is the hypotenuse \( x \). Plugging in the values:
\[
19^2 + 2^2 = x^2
\]
Calculating \( 19^2 \) and \( 2^2 \):
\[
19^2 = 361
\]
\[
2^2 = 4
\]
Now, substitute these back into the equation:
\[
361 + 4 = x^2
\]
Add the values:
\[
365 = x^2
\]
Now, take the square root to find \( x \):
\[
x = \sqrt{365}
\]
Calculating the square root:
\[
x \approx 19.1
\]
So the length of the hypotenuse \( x \) is approximately **19.1** when rounded to the nearest tenth.
\[
a^2 + b^2 = c^2
\]
In this case, \( c \) is the hypotenuse \( x \). Plugging in the values:
\[
19^2 + 2^2 = x^2
\]
Calculating \( 19^2 \) and \( 2^2 \):
\[
19^2 = 361
\]
\[
2^2 = 4
\]
Now, substitute these back into the equation:
\[
361 + 4 = x^2
\]
Add the values:
\[
365 = x^2
\]
Now, take the square root to find \( x \):
\[
x = \sqrt{365}
\]
Calculating the square root:
\[
x \approx 19.1
\]
So the length of the hypotenuse \( x \) is approximately **19.1** when rounded to the nearest tenth.
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