Looking at the periodic table, determine the number of valence electrons present in a following neutral atoms.

Question

Column A
1.
Oxygen (O):
Oxygen (O)
2.
Aluminium (Al):
Aluminium (Al)
3.
Neon (Ne):
Neon (Ne)
4.
Silicion (Si):
Silicion (Si)
5.
Magnesium (Mg):
Magnesium (Mg)
6.
Iodine (I):
Iodine (I)
7.
Lithium (Li):
Lithium (Li)
8.
Nitrogen (N):
Nitrogen (N)
Column B
a.4 valence electrons
b.8 valence electrons
c.6 valence electrons
d.3 valence electrons
e.1 valence electrons
f.7 valence electrons
g.2 valence electrons
h.5 valence electrons

Answer 1

To determine the number of valence electrons for each of the elements listed in Column A, we can refer to their positions in the periodic table. Valence electrons correspond to the outermost electrons, and the group number can help indicate this for main group elements.

Here are the valence electrons for each element:

1. Oxygen (O): 6 valence electrons
2. Aluminium (Al): 3 valence electrons
3. Neon (Ne): 8 valence electrons
4. Silicon (Si): 4 valence electrons
5. Magnesium (Mg): 2 valence electrons
6. Iodine (I): 7 valence electrons
7. Lithium (Li): 1 valence electron
8. Nitrogen (N): 5 valence electrons

Now, matching these with the choices in Column B:

• Oxygen (O): 6 valence electrons (c)
• Aluminium (Al): 3 valence electrons (d)
• Neon (Ne): 8 valence electrons (b)
• Silicon (Si): 4 valence electrons (a)
• Magnesium (Mg): 2 valence electrons (g)
• Iodine (I): 7 valence electrons (f)
• Lithium (Li): 1 valence electron (e)
• Nitrogen (N): 5 valence electrons (h)

Therefore, here are the matches:

1. Oxygen (O) - c (6 valence electrons)
2. Aluminium (Al) - d (3 valence electrons)
3. Neon (Ne) - b (8 valence electrons)
4. Silicon (Si) - a (4 valence electrons)
5. Magnesium (Mg) - g (2 valence electrons)
6. Iodine (I) - f (7 valence electrons)
7. Lithium (Li) - e (1 valence electron)
8. Nitrogen (N) - h (5 valence electrons)