To solve the problem systematically, let's break it down step-by-step.
Part a: Determine the final image's quadrant
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Coordinates of triangle QRS:
- \(Q(-8, 4)\)
- \(R(-5, 8)\)
- \(S(-3, 3)\)
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First Transformation \((x,y) \to (x+4, y-6)\):
- For Q: \[ Q' = (-8+4, 4-6) = (-4, -2) \]
- For R: \[ R' = (-5+4, 8-6) = (-1, 2) \]
- For S: \[ S' = (-3+4, 3-6) = (1, -3) \]
So, the coordinates after the first transformation are:
- \(Q'(-4, -2)\)
- \(R'(-1, 2)\)
- \(S'(1, -3)\)
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Second Transformation \((x,y) \to (x+5, y-3)\):
- For Q': \[ Q'' = (-4+5, -2-3) = (1, -5) \]
- For R': \[ R'' = (-1+5, 2-3) = (4, -1) \]
- For S': \[ S'' = (1+5, -3-3) = (6, -6) \]
So, the coordinates after the second transformation are:
- \(Q''(1, -5)\)
- \(R''(4, -1)\)
- \(S''(6, -6)\)
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Determine the quadrant:
- All points have positive x-values and negative y-values:
- \(Q''(1, -5)\) lies in Quadrant IV
- \(R''(4, -1)\) lies in Quadrant IV
- \(S''(6, -6)\) lies in Quadrant IV
- All points have positive x-values and negative y-values:
Answer for Part a: The final image, triangle \(ΔQ''R''S''\), will be located in Quadrant IV.
Part b: Create the rule for the composition transformation
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First transformation:
- \((x, y) \to (x + 4, y - 6)\)
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Second transformation:
- \((x, y) \to (x + 5, y - 3)\)
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Composition of transformations:
- When you apply the first transformation, you transform coordinates \( (x, y) \) into \((x + 4, y - 6)\). Then, apply the second transformation to this output: \[ (x + 4 + 5, (y - 6) - 3) = (x + 9, y - 9) \]
Thus, the rule for the composition transformation is: \[ (x, y) \to (x + 9, y - 9) \]
Answer for Part b: The rule for the composition transformation is \((x + 9, y - 9)\).