Let's analyze the given exponential equation \( m(p) = 20(2^p) \).
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Domain (p-values):
- The variable \( p \) represents the number of people who opt to pass the money on. In this scenario, since \( p \) counts the number of exchanges and must be a non-negative integer, the domain includes values such that \( p \geq 0 \) (not 20). Hence, the correct statement about the domain would be that the domain includes non-negative integers: \( p \geq 0 \).
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Range (m-values):
- We see that \( m(p) = 20(2^p) \). Since \( 2^p \) is always positive for any value of \( p \) in its domain (including \( p = 0 \) which gives \( m(0) = 20 \)), the smallest value \( m \) can take is 20 when \( p=0 \), and it increases indefinitely as \( p \) increases. Thus, the range of \( m \) is \( m \geq 20 \).
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Behavior of m as p increases:
- As \( p \) increases, \( 2^p \) increases exponentially. Therefore, \( m(p) = 20(2^p) \) also increases exponentially. This means that \( m \) increases quickly as \( p \) increases. So, the statement “As p increases, m increases quickly at first and then slowly” is incorrect — \( m \) does not increase slowly after initially accelerating; it continues to increase quickly.
Based on this analysis:
- The correct statements are: The range (m-values) includes the values \( m \geq 20 \).
The other statements about domain and the behavior of m as p increases are incorrect.