Supposed that hotdogs come in packs of nine and buns come in packs of seven. John bought the same number of hotdogs as buns. It was the least number for each for which this was possible. How many hotdogs did he buy? How many packs of hotdogs did he buy how many packs of buns did he buy

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1 month ago

Let's denote the number of packs of hotdogs John bought as \( h \) and the number of packs of buns as \( b \). According to the problem, each pack of hotdogs contains 9 hotdogs, and each pack of buns contains 7 buns. Since John has the same number of hotdogs as buns, we can express this relationship mathematically:

\[ 9h = 7b \]

To find the least number of hotdogs and buns, we need the smallest positive integers \( h \) and \( b \) for which this equation holds. Rearranging the equation gives us:

\[ \frac{h}{b} = \frac{7}{9} \]

This indicates that \( h \) and \( b \) can be expressed in terms of a common multiple. We can let:

\[ h = 7k \quad \text{and} \quad b = 9k \]

for some integer \( k \). Substituting back into the expression for the number of hotdogs and buns gives:

\[ \text{Number of hotdogs} = 9h = 9(7k) = 63k \]

\[ \text{Number of buns} = 7b = 7(9k) = 63k \]

Both approaches yield the same total number, \( 63k \), meaning the least common case occurs when \( k = 1 \).

Thus, the least number of hotdogs and buns is 63, and they can be calculated as follows:

  • Number of hotdogs: \( 63 \)
  • Number of buns: \( 63 \)

Now calculating the number of packs:

  • Number of packs of hotdogs \( h = 7 \) (since \( 63 \div 9 = 7 \))
  • Number of packs of buns \( b = 9 \) (since \( 63 \div 7 = 9 \))

In summary, John bought:

  • 63 hotdogs
  • 7 packs of hotdogs
  • 9 packs of buns