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How Cells Make Proteins Quick Check 3 of 53 of 5 Items Question The amino acid serine is coded by the mRNA codon AGU. What is the base sequence of the DNA gene that originally produced this mRNA codon?(1 point) Responses AGU AGU UCA UCA TCC TCC TCA TCA Skip to navigation page 16 of 16

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To find the base sequence of the DNA gene that originally produced the mRNA codon AGU, you need to consider the relationship between DNA and mRNA.

mRNA is transcribed from DNA, and during this process, adenine (A) in DNA pairs with uracil (U) in RNA, while cytosine (C) pairs with guanine (G). Therefore, to convert the mRNA codon AGU back to its corresponding DNA strand, we need to consider the complementary base pairs.

The mRNA sequence AGU would correspond to the following DNA sequence:

  • A (from DNA) pairs with U (in RNA),
  • G (from DNA) pairs with C (in RNA),
  • T (from DNA) pairs with A (in RNA).

The DNA sequence coding for this mRNA would therefore be:

TCA

So, the base sequence of the DNA gene that originally produced this mRNA codon AGU is TCA. None of the other options listed (AGU, UCA, TCC, TCA) were other forms based on the transcription rules directly from DNA to RNA.

If you are looking for the direct sequence to provide, the one that pairs and reads directly as mRNA is:

TCA