To determine the high or low point of the parabola described by the quadratic equation \( y = -6x^2 + 3x + 8 \), we need to analyze the equation.
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Identifying the vertex: In a quadratic equation of the form \( y = ax^2 + bx + c \), the x-coordinate of the vertex (which gives the location of the high or low point depending on the direction the parabola opens) can be found using the formula: \[ x = -\frac{b}{2a} \] Here, \( a = -6 \) and \( b = 3 \). \[ x = -\frac{3}{2 \times -6} = -\frac{3}{-12} = \frac{1}{4} = 0.25 \]
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Calculating the y-coordinate at \( x = 0.25 \): Substitute \( x = 0.25 \) into the equation to find the corresponding y-coordinate: \[ y = -6(0.25)^2 + 3(0.25) + 8 \] \[ = -6(0.0625) + 0.75 + 8 \] \[ = -0.375 + 0.75 + 8 \] \[ = 8.375 \]
Therefore, the vertex of the parabola is at \( (0.25, 8.375) \).
- Analysis of the vertex: Since the coefficient \( a \) is negative (\( -6 \)), the parabola opens downwards, which means that the vertex is the high point of the parabola.
Given the analysis above, the correct response regarding the various points is:
(0.25, 8.375) is the high point on the parabola.