To solve the quadratic equation \( x^2 + 4x - 32 = 0 \) by factoring, we look for two numbers that multiply to \(-32\) (the constant term) and add to \(4\) (the coefficient of the linear term).
The numbers \(8\) and \(-4\) meet these criteria because:
- \(8 \times (-4) = -32\)
- \(8 + (-4) = 4\)
Thus, we can factor the quadratic as follows:
\[ (x + 8)(x - 4) = 0 \]
Therefore, the correct factored form is:
\((x + 8)(x - 4) = 0\)