Identify the table that demonstrates a proportional relationship.(1 point)

Responses

x y
4 2
9 3
16 4
x y 4 2 9 3 16 4

x y
10 2
15 3
40 8


x y 10 2 15 3 40 8

x y
2 10
5 20
6 30
x y 2 10 5 20 6 30

x y
8 2
12 3
40 4

1 answer

To identify a proportional relationship, we need to check if the ratio of \( y \) to \( x \) is constant for each pair of values in the table.

  1. First table:

    • \( y = 2 \) when \( x = 4 \) → \( \frac{y}{x} = \frac{2}{4} = 0.5 \)
    • \( y = 3 \) when \( x = 9 \) → \( \frac{y}{x} = \frac{3}{9} = \frac{1}{3} \)
    • \( y = 4 \) when \( x = 16 \) → \( \frac{y}{x} = \frac{4}{16} = \frac{1}{4} \)

    The ratios are not constant.

  2. Second table:

    • \( y = 2 \) when \( x = 10 \) → \( \frac{y}{x} = \frac{2}{10} = 0.2 \)
    • \( y = 3 \) when \( x = 15 \) → \( \frac{y}{x} = \frac{3}{15} = 0.2 \)
    • \( y = 8 \) when \( x = 40 \) → \( \frac{y}{x} = \frac{8}{40} = 0.2 \)

    The ratios are constant at 0.2.

  3. Third table:

    • \( y = 10 \) when \( x = 2 \) → \( \frac{y}{x} = \frac{10}{2} = 5 \)
    • \( y = 20 \) when \( x = 5 \) → \( \frac{y}{x} = \frac{20}{5} = 4 \)
    • \( y = 30 \) when \( x = 6 \) → \( \frac{y}{x} = \frac{30}{6} = 5 \)

    The ratios are not constant.

  4. Fourth table:

    • \( y = 2 \) when \( x = 8 \) → \( \frac{y}{x} = \frac{2}{8} = 0.25 \)
    • \( y = 3 \) when \( x = 12 \) → \( \frac{y}{x} = \frac{3}{12} = 0.25 \)
    • \( y = 4 \) when \( x = 40 \) → \( \frac{y}{x} = \frac{4}{40} = 0.1 \)

    The ratios are not constant.

Based on this analysis, the second table demonstrates a proportional relationship, as the ratio of \( y \) to \( x \) is constant (0.2).