2sin^x(sqrt2/2) = -1
sin x = -1/sqrt2 = - sqrt 2 /2
x = pi + pi/4 = 5 pi/4
x = 2 pi - pi/4 = 7 pi /4
so I agree with you but you seem to have a typo
2) Use the sum and difference identites
sin[x + pi/4] + sin[x-pi/4] = -1
sinx cospi/4 + cosxsin pi/4 + sinx cos pi/4 - cosx sin pi/4 = -1
2 sin x cos pi/4 =-1
cos pi/4 = sqr2/2
2sin^x(sqrt2/2) = -1
sin x = -sqrt2
x = 7pi/4 and 5pi/4
Am I correct?
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