The given equation is \( x^2 + 4x + 3 = 0 \). This is a quadratic equation in the standard form \( ax^2 + bx + c = 0 \).
- The value of \( a \) is 1 (the coefficient of \( x^2 \)).
- The value of \( b \) is 4 (the coefficient of \( x \)).
- The value of \( c \) is 3 (the constant term).
To find one solution to the equation, we can factor it or use the quadratic formula.
Factoring gives: \[ (x + 1)(x + 3) = 0 \] Setting each factor to zero gives the solutions:
- \( x + 1 = 0 \) → \( x = -1 \)
- \( x + 3 = 0 \) → \( x = -3 \)
One solution to the equation is -1 (or you could also state -3, as both are valid solutions).
Here is the complete answer:
- The value of \( a \) is 1.
- The value of \( b \) is 4.
- The value of \( c \) is 3.
- One solution to the equation is -1.